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Player Profile

Player:

(Eg: Carlsen,Magnus)

Steel, Bradley



Years:	1994-1995
Number of games:	15
Number of wins:	4
Number of draws:	4
Number of losses:	7
White score:	4/8 (50% - Average Elo: 1080.5)
Black score:	2/7 (28.57% - Average Elo: 1671)

Games
White wins
White draws
White losses
Black wins
Black losses

Top wins

Steel, Bradley (1185) - Moylan, Andrew (1135), AUS-ch U18, Gold Coast (B13) - 1994

Steel, Bradley - Dao, Hung, AUS-ch U18, Canberra (B23) - 1995

Martin, Jared - Steel, Bradley, AUS-ch U18, Canberra (C00) - 1995

Ayling, Simon D - Steel, Bradley, AUS-ch U18, Canberra (C07) - 1995

Steel, Bradley - ? (8)

Coventry, James (½/1)

Dao, Hung (1/1)

Feldman, Daniel (0/1)

Hummel, Mark (½/1)

Klimenko, Veronica (½/1)

Moylan, Andrew (1/1)

Switzer, Timothy (0/1)

Szuveges, Narelle (½/1)

? - Steel, Bradley (7)

Ayling, Simon D (1/1)

Cheung, Ernest Pak Shing (0/1)

Cordover, David (0/1)

Martin, Jared (1/1)

Nield, David (0/1)

Pizzato, Charles (0/1)

Stitt, Daniel (0/1)

Openings played as White (6)

C30 King's Gambit Declined (1.e4 e5 2.f4)
Average Elo: 0
Result: 1/2 = 50%

C29 Vienna Gambit (1.e4 e5 2.Nc3 Nf6 3.f4)
Average Elo: 0
Result: ½/2 = 25%

B23 Sicilian, Closed (1.e4 c5 2.Nc3)
Average Elo: 0
Result: 1/1 = 100%

B21 Sicilian, 2.f4 and 2.d4 (1.e4 c5 2.f4)
Average Elo: 1026
Result: 0/1 = 0%

C02 French, Advance (1.e4 e6 2.d4 d5 3.e5)
Average Elo: 0
Result: ½/1 = 50%

B13 Caro-Kann, Exchange (1.e4 c6 2.d4 d5 3.exd5 cxd5)
Average Elo: 1135
Result: 1/1 = 100%

Openings played as Black (6)

C00 French Defense (1.e4 e6)
Average Elo: 1643
Result: 1/2 = 50%

C08 French, Tarrasch, Open, 4.ed ed (1.e4 e6 2.d4 d5 3.Nd2 c5 4.exd5 exd5)
Average Elo: 1699
Result: 0/1 = 0%

D04 Queen's Pawn Game (1.d4 d5 2.Nf3 Nf6 3.e3)
Average Elo: 0
Result: 0/1 = 0%

E01 Catalan, Closed (1.d4 Nf6 2.c4 e6 3.g3 d5 4.Bg2)
Average Elo: 0
Result: 0/1 = 0%

C07 French, Tarrasch (1.e4 e6 2.d4 d5 3.Nd2 c5)
Average Elo: 0
Result: 1/1 = 100%

C01 French, Exchange (1.e4 e6 2.d4 d5 3.exd5 exd5 4.Nc3 Nf6 5.Bg5)
Average Elo: 0
Result: 0/1 = 0%